Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 2)
2.
The conductive loop on the rotor of a simple two-pole, single-phase generator rotates at a rate of 400 rps. The frequency of the induced output voltage is
Discussion:
38 comments Page 2 of 4.
Surya said:
8 years ago
N= 120f/p.
F= 400*60*2/120.
F= 400.
F= 400*60*2/120.
F= 400.
Waheed ullah khattak said:
9 years ago
If we change RPS to RPM then we should have to divide by 60.
Bhanu said:
9 years ago
Great job @Jansi.
Fatima said:
9 years ago
@Hassan.
Formula contains Ns syncronous speed ,Ns = (( 120 * f ) /p).
Formula contains Ns syncronous speed ,Ns = (( 120 * f ) /p).
Hassan said:
9 years ago
How did you guys get that 120?
Rakshith said:
9 years ago
As we all know,
Ns = ( (120 * f) /p); Here Ns is in rpm. Therefore,
Ns = Ns/60 rps.
So,
Ns = ((2 * f)/p),
And f = ((p * ns)/2),
f = 2 * 400/2,
f = 400Hz.
Ns = ( (120 * f) /p); Here Ns is in rpm. Therefore,
Ns = Ns/60 rps.
So,
Ns = ((2 * f)/p),
And f = ((p * ns)/2),
f = 2 * 400/2,
f = 400Hz.
Jansi said:
10 years ago
Here given data is:
No. of poles = 2;
Speed (N) = 400 rps;
Usually speed is calculated in rpm. So here we convert 400 rps (revolution per second) in terms of rpm (revolutions per minute).
As 1 min = 60 sec; we multiply 400x60 rpm;
As we know N = 120f/p.
f = np/120;
f = 400x60x2/120.
f = 400 hz.
So hope no one has any doubts regarding this explanation.
No. of poles = 2;
Speed (N) = 400 rps;
Usually speed is calculated in rpm. So here we convert 400 rps (revolution per second) in terms of rpm (revolutions per minute).
As 1 min = 60 sec; we multiply 400x60 rpm;
As we know N = 120f/p.
f = np/120;
f = 400x60x2/120.
f = 400 hz.
So hope no one has any doubts regarding this explanation.
(1)
Kalai sasi said:
10 years ago
Its a number of poles.
Mrityunjay said:
1 decade ago
Please any one tell from where 2 is came?
NAvya said:
1 decade ago
Where 1sec=1/60min. But how you multiplied 60 in the speed.
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