Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion :: Alternating Current and Voltage - General Questions (Q.No.8)

8. 

A 20 kHz pulse waveform consists of pulses that are 15 s wide. The duty cycle

[A]. is 1%
[B]. is 30%
[C]. is 100%
[D]. cannot be determined

Answer: Option B

Explanation:

No answer description available for this question.

Anand Joshi said: (Aug 17, 2011)  
Now

time t=1/frequency
=1/20000
=.00005

Now

duty cycle=.000015/0.00005
=.3
and hence ans is .3*100=30%

Soumyak Nanda said: (Nov 21, 2011)  
Thanks anand.

Satish Gnd said: (Mar 22, 2012)  
Thanks anand

Darwin Bhandari said: (May 18, 2012)  
Duty cycle = Pulse duration/Total period of signal.
Pulse duration = 15us
Period = 1/20kHz =.00005
So D = 0.3 = 30%

Abinash Chatterjee said: (Feb 11, 2014)  
Duty Cycle = Time of Signal Active/Total period.
Total Period = 1/frequency.

Therefore,
D = T/PX100%.
D = 15 X 10^-6 X 20 X 10^3 X 100%.
D = 30%.

Abinash Chatterjee said: (Feb 11, 2014)  
Duty Cycle = Time of Signal Active/Total period.
Total Period = 1/frequency.

Therefore,
D = T/PX100%.
D = 15 X 10^-6 X 20 X 10^3 X 100%.
D = 30%.

Arindam Sarkar said: (Jan 8, 2016)  
D = (Ton/T)*100%.

T = 1/f = 1/200000 = 0.00005 s.

Ton = 15us = 15*10^-6s.

D = 0.3 = 30%.

Shani Pawar said: (Jan 8, 2019)  
Thanks for the answer @Anand Joshi.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.