# Electrical Engineering - Alternating Current and Voltage - Discussion

### Discussion :: Alternating Current and Voltage - General Questions (Q.No.8)

8.

A 20 kHz pulse waveform consists of pulses that are 15 s wide. The duty cycle

 [A]. is 1% [B]. is 30% [C]. is 100% [D]. cannot be determined

Explanation:

No answer description available for this question.

 Anand Joshi said: (Aug 17, 2011) Now time t=1/frequency =1/20000 =.00005 Now duty cycle=.000015/0.00005 =.3 and hence ans is .3*100=30%

 Soumyak Nanda said: (Nov 21, 2011) Thanks anand.

 Satish Gnd said: (Mar 22, 2012) Thanks anand

 Darwin Bhandari said: (May 18, 2012) Duty cycle = Pulse duration/Total period of signal. Pulse duration = 15us Period = 1/20kHz =.00005 So D = 0.3 = 30%

 Abinash Chatterjee said: (Feb 11, 2014) Duty Cycle = Time of Signal Active/Total period. Total Period = 1/frequency. Therefore, D = T/PX100%. D = 15 X 10^-6 X 20 X 10^3 X 100%. D = 30%.

 Abinash Chatterjee said: (Feb 11, 2014) Duty Cycle = Time of Signal Active/Total period. Total Period = 1/frequency. Therefore, D = T/PX100%. D = 15 X 10^-6 X 20 X 10^3 X 100%. D = 30%.

 Arindam Sarkar said: (Jan 8, 2016) D = (Ton/T)*100%. T = 1/f = 1/200000 = 0.00005 s. Ton = 15us = 15*10^-6s. D = 0.3 = 30%.

 Shani Pawar said: (Jan 8, 2019) Thanks for the answer @Anand Joshi.