Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 8)
8.
A 20 kHz pulse waveform consists of pulses that are 15 
s wide. The duty cycle
s wide. The duty cycleDiscussion:
8 comments Page 1 of 1.
Shani Pawar said:
7 years ago
Thanks for the answer @Anand Joshi.
(1)
Arindam Sarkar said:
10 years ago
D = (Ton/T)*100%.
T = 1/f = 1/200000 = 0.00005 s.
Ton = 15us = 15*10^-6s.
D = 0.3 = 30%.
T = 1/f = 1/200000 = 0.00005 s.
Ton = 15us = 15*10^-6s.
D = 0.3 = 30%.
Abinash Chatterjee said:
1 decade ago
Duty Cycle = Time of Signal Active/Total period.
Total Period = 1/frequency.
Therefore,
D = T/PX100%.
D = 15 X 10^-6 X 20 X 10^3 X 100%.
D = 30%.
Total Period = 1/frequency.
Therefore,
D = T/PX100%.
D = 15 X 10^-6 X 20 X 10^3 X 100%.
D = 30%.
(2)
Abinash Chatterjee said:
1 decade ago
Duty Cycle = Time of Signal Active/Total period.
Total Period = 1/frequency.
Therefore,
D = T/PX100%.
D = 15 X 10^-6 X 20 X 10^3 X 100%.
D = 30%.
Total Period = 1/frequency.
Therefore,
D = T/PX100%.
D = 15 X 10^-6 X 20 X 10^3 X 100%.
D = 30%.
Darwin Bhandari said:
1 decade ago
Duty cycle = Pulse duration/Total period of signal.
Pulse duration = 15us
Period = 1/20kHz =.00005
So D = 0.3 = 30%
Pulse duration = 15us
Period = 1/20kHz =.00005
So D = 0.3 = 30%
Satish gnd said:
1 decade ago
Thanks anand
Soumyak nanda said:
1 decade ago
Thanks anand.
Anand joshi said:
1 decade ago
Now
time t=1/frequency
=1/20000
=.00005
Now
duty cycle=.000015/0.00005
=.3
and hence ans is .3*100=30%
time t=1/frequency
=1/20000
=.00005
Now
duty cycle=.000015/0.00005
=.3
and hence ans is .3*100=30%
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers