# Electrical Engineering - Alternating Current and Voltage - Discussion

### Discussion :: Alternating Current and Voltage - General Questions (Q.No.16)

16.

Two series resistors are connected to an ac source. If there are 7.5 V rms across one resistor and 4.2 V rms across the other, the peak source voltage is

 [A]. 16.54 V [B]. 1.65 V [C]. 10.60 V [D]. 5.93 V

Explanation:

No answer description available for this question.

 Raju T said: (Feb 28, 2011) Peak voltage=(V1rms+V2rms)/1.414

 Vinay said: (Apr 18, 2011) peak source voltage= (v1rms+v2rms)*1.414 = (7.5+4.2)*1.414 = 16.54

 Balbir Kairay said: (Nov 16, 2011) If in the statement component connect in series then component value will be add on all time.

 Siddu said: (Jan 31, 2012) Here 7.5/.707 = 10.6 4.2/.707 = 5.800000 10.6 + 5.8 = 16.5

 Uttam Kumar Sarkar said: (Nov 20, 2012) Vrms = Vmax/1.414 Vmax = Vrms*1.414 = (7.5+4.2)*1.414 = 16.54 Volt

 Hit B said: (Feb 15, 2016) As this is AC Circuit, then how can we add two voltages algebraically. We have to do complex summation.

 Pranjal said: (May 13, 2017) Yes, you are correct. @HIT B. We cannot add them directly as they are in AC circuit.

 Parth said: (Jun 23, 2017) Hypothetically they are in phase. As phase difference is not given. Thus, their direct addition is possible.

 Ebenesar said: (Apr 7, 2018) Rms value is equal to dc voltage so we can add.

 Vinny said: (May 5, 2018) R1+R2=7.5+4.2=11.7. Vmax=11.7*1.414=16.543v.