Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion :: Alternating Current and Voltage - General Questions (Q.No.16)

16. 

Two series resistors are connected to an ac source. If there are 7.5 V rms across one resistor and 4.2 V rms across the other, the peak source voltage is

[A]. 16.54 V
[B]. 1.65 V
[C]. 10.60 V
[D]. 5.93 V

Answer: Option A

Explanation:

No answer description available for this question.

Raju T said: (Feb 28, 2011)  
Peak voltage=(V1rms+V2rms)/1.414

Vinay said: (Apr 18, 2011)  
peak source voltage= (v1rms+v2rms)*1.414
= (7.5+4.2)*1.414 = 16.54

Balbir Kairay said: (Nov 16, 2011)  
If in the statement component connect in series then component value will be add on all time.

Siddu said: (Jan 31, 2012)  
Here 7.5/.707 = 10.6

4.2/.707 = 5.800000

10.6 + 5.8 = 16.5

Uttam Kumar Sarkar said: (Nov 20, 2012)  
Vrms = Vmax/1.414
Vmax = Vrms*1.414
= (7.5+4.2)*1.414
= 16.54 Volt

Hit B said: (Feb 15, 2016)  
As this is AC Circuit, then how can we add two voltages algebraically. We have to do complex summation.

Pranjal said: (May 13, 2017)  
Yes, you are correct. @HIT B.

We cannot add them directly as they are in AC circuit.

Parth said: (Jun 23, 2017)  
Hypothetically they are in phase.
As phase difference is not given.
Thus, their direct addition is possible.

Ebenesar said: (Apr 7, 2018)  
Rms value is equal to dc voltage so we can add.

Vinny said: (May 5, 2018)  
R1+R2=7.5+4.2=11.7.

Vmax=11.7*1.414=16.543v.

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