Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 9)
9.
If the peak of a sine wave is 13 V, the peak-to-peak value is
Discussion:
7 comments Page 1 of 1.
Neeraj Kumar said:
5 years ago
Thanks all for explaining the answer.
Anirudhha said:
6 years ago
peak to peak means=2*peak valve.
= 2*13.
= 26v.
= 2*13.
= 26v.
Milan Mondal said:
8 years ago
Peak to peak means= 2 * peak value.
= 2*13,
= 26 v.
= 2*13,
= 26 v.
Marshall said:
10 years ago
Positive peak is 13v, negative peak is 13v also 13v.
Peak to peak = Positive peak + Negative peak = 13 v + 13 v = 26 v amplitude.
Peak to peak = Positive peak + Negative peak = 13 v + 13 v = 26 v amplitude.
Naveed mengal said:
10 years ago
Peak to peak.
Peak value multiply into 2.
Result is 26v.
Peak value multiply into 2.
Result is 26v.
ESWAR said:
1 decade ago
Peak-to-peak (pk-pk) is the difference between the maximum positive and the maximum negative amplitudes of a waveform, as shown below. If there is no direct current (DC) component in an alternating current (AC) wave, then the pk-pk amplitude is twice the peak amplitude.
Yanusha said:
1 decade ago
Peak to peak voltage = 2Vp
=2*13=26v
=2*13=26v
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