Discussion :: Alternating Current and Voltage - General Questions (Q.No.9)
If the peak of a sine wave is 13 V, the peak-to-peak value is
Answer: Option C
No answer description available for this question.
|Yanusha said: (Sep 22, 2011)|
|Peak to peak voltage = 2Vp
|Eswar said: (Jan 22, 2014)|
|Peak-to-peak (pk-pk) is the difference between the maximum positive and the maximum negative amplitudes of a waveform, as shown below. If there is no direct current (DC) component in an alternating current (AC) wave, then the pk-pk amplitude is twice the peak amplitude.|
|Naveed Mengal said: (Dec 23, 2015)|
|Peak to peak.
Peak value multiply into 2.
Result is 26v.
|Marshall said: (Feb 13, 2016)|
|Positive peak is 13v, negative peak is 13v also 13v.
Peak to peak = Positive peak + Negative peak = 13 v + 13 v = 26 v amplitude.
|Milan Mondal said: (Aug 2, 2017)|
|Peak to peak means= 2 * peak value.
= 26 v.
|Anirudhha said: (Dec 26, 2019)|
|peak to peak means=2*peak valve.
|Neeraj Kumar said: (May 31, 2020)|
|Thanks all for explaining the answer.|
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.