Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 12)
12.
A sine wave of 15 kHz is changing at a faster rate than a sine wave with a frequency of
25 kHz
12 kHz
18 kHz
1.3 MHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Ruchi said:   8 years ago
T= 1/f so lower the frequency higher the time period so 12k<15k.

Sasikumar paramasivam said:   9 years ago
t = 1/f.

The time is indirectly proportional to frequency.
So the lesser value of frequency from giving value will be a faster rate.

Ishwar Rajput said:   9 years ago
It means that frequency is nothing but cycle per second. So 12 kHz is slower than the 15 kHz. Other rates are higher than the 15 kHz.

Jansi said:   10 years ago
Frequency is inversely proportional to time period;.

So now sine wave with 15khz changes faster than sine wave with 12khz;
(1)

Goutami said:   1 decade ago
Logically we can say here one thing.

Given that 15khz (let it be f1) is changing at a faster rate than some freq (let it be f2). So the time of f1 should be less than f2 (i.e. , t1<t2).

Hence t2 is more, in a sense f2 is less and from options it is clear that f2 = 12khz<f1.

AJAY CHITKARA(1277) said:   1 decade ago
Frequency rate is inversely proportional to original frequency by +/-3kHz.
(1)

RAVI KUMAWAT said:   1 decade ago
Because the frequency is cycle per second, upper frequency pass more cycle than lesser frequency. So 12 kHz is lesser than 15 kHz.

Sivakumar said:   1 decade ago
Logically we can approach this prob.

Only 12 khz is lesser than the freq that is given in question. Others are greater. So obviously option B ll b d answer.

Karthick said:   1 decade ago
Please explain this.

Rahul said:   1 decade ago
Lesser the amplitude more will be changing rate.

Post your comments here:

Your comments will be displayed after verification.