Digital Electronics - The 8051 Microcontroller - Discussion
Discussion Forum : The 8051 Microcontroller - General Questions (Q.No. 9)
9.
MOV A, @ R1 will:
Discussion:
7 comments Page 1 of 1.
Pradip said:
1 decade ago
Indirect mode of addressing
Shruti said:
1 decade ago
Its an indirect mode of addressing. @ acts as a pointer to the contents of the memory of which address is in R1..and thus being source..it copies that data to accumlator being destination.
NARENDRA said:
1 decade ago
@indicate: It's Indirect mode of addressing
Abhi said:
1 decade ago
Ri=register (R0 to R1)
Rn=register (R0 to R7)
# = immediat data
@ = indirect ram
Rn=register (R0 to R7)
# = immediat data
@ = indirect ram
Surya said:
1 decade ago
This is indirect addressing mode.
EX: R=Register(R1-R3)
@ indictes content of register(indirectly)
Its an indirect mode of addressing. @ acts as a pointer
It copies that data to accumlator being destination.
EX: R=Register(R1-R3)
@ indictes content of register(indirectly)
Its an indirect mode of addressing. @ acts as a pointer
It copies that data to accumlator being destination.
Lokesh said:
10 years ago
@ indicates indirect access of memory. So the contents of that memory location into accumulator.
Chethan said:
9 years ago
It is an indirect addressing mode,
Assume,
mov R1,#1000
mov A,@R1
What it explain is in the first instruction value 1000 moves into R1 (immediate address), in the second instruction, the value present in the 1000 (here thousand acts as an address) moves into the A reg.
Assume,
mov R1,#1000
mov A,@R1
What it explain is in the first instruction value 1000 moves into R1 (immediate address), in the second instruction, the value present in the 1000 (here thousand acts as an address) moves into the A reg.
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