IndiaBIX

Digital Electronics - The 8051 Microcontroller - Discussion

Discussion Forum : The 8051 Microcontroller - General Questions (Q.No. 4)
The 8051 Microcontroller
4.
The address space of the 8051 is divided into four distinct areas: internal data, external data, internal code, and external code.
True
False
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
8 comments Page 1 of 1.
Jithendra reddy said:   7 years ago
Thanks to all of you, now I got the correct explanation for the answer.
Unknown said:   8 years ago
8051 consists of program memory and data memory. That is 256 kbytes out of which 128 bytes are for internal memory and other 128 kbytes are for external memory. These 128 kbytes are divided into 64 kbytes for program memory and other 64 kbytes for data memory.

Program memory can be accessed through program counter and fetch instructions and data memory can be accessed using dptr.
(1)
Finu said:   8 years ago
Could you please tell how the address memory divided into 4?
(1)
Bubli said:   9 years ago
The address memory divided into 4 distinct area how?
Satyanarayana.putta said:   1 decade ago
8051 has two types of memories that are ROM ,RAM

RAM stores temporary data
ROM stores permanent data i.e)code

8051 has internally 128 bytes RAM,4 Kbytes ROM
We are connecting to externally RAM,ROM up to 64Kbyte of memory

So the answer is option A.
Priyanka said:   1 decade ago
Do these bank addresses indicate the internal data, external data, internal code, and external code?
Karu said:   1 decade ago
Can you explain Which address space. Because internal RAM divided into bank, bit addressable area, Ggeneral purpose RAM. Then how. ?
Mido said:   1 decade ago
bank addresses 0 , 1 ,2 ,3 ,4
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers