Digital Electronics - Signals and Switches - Discussion
Discussion Forum : Signals and Switches - General Questions (Q.No. 2)
2.
What is the frequency of a clock waveform if the period of that waveform is
1.25
s?
1.25
s?Discussion:
6 comments Page 1 of 1.
Shashank said:
10 years ago
= 100/125*10^-8.
= (4/5)*10^6.
= (0.8)*10^6.
= (0.8)*10^6.
= 8 MHZ.
= (4/5)*10^6.
= (0.8)*10^6.
= (0.8)*10^6.
= 8 MHZ.
Ananya said:
1 decade ago
Just 1/1.25 * 10^-6 = 10^6 * 100/ 125 = 0.8 MHz.
Sagar said:
1 decade ago
1.25us = 125x10^-8 sec.
Thus, 1/T = f.
Hence, f = 1/125x10^-8 sec.
f = 800kHz = 0.8MHz.
Thus, 1/T = f.
Hence, f = 1/125x10^-8 sec.
f = 800kHz = 0.8MHz.
Vivek said:
1 decade ago
By the formula of frequency we can find the frequency of clock
waveform.
Time period(t)is given of that waveform is=1.25microseconds
f=1/t
Where T is the time taken by the clock waveform.
f=(1/1.25)
And f=0.8mhz
waveform.
Time period(t)is given of that waveform is=1.25microseconds
f=1/t
Where T is the time taken by the clock waveform.
f=(1/1.25)
And f=0.8mhz
Jitu said:
1 decade ago
f=1/T so that 1/1.25micro sec = 0.8Mhz
Veeresh said:
1 decade ago
Please explain
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers