Digital Electronics - Shift Registers - Discussion
Discussion Forum : Shift Registers - General Questions (Q.No. 36)
36.
When an 8-bit serial in/serial out shift register is used for a 20 
s time delay, the clock frequency is ________.
s time delay, the clock frequency is ________.Discussion:
3 comments Page 1 of 1.
Vivek said:
7 years ago
total delay(Td) provided by SISO = n*Tclk.
20 micro-sec = 8*Tclk,
Tclk = (20 micro-sec/8),
Fclk = (1/Tclk) = (8/20 micro-sec) = (8000/20)kHz = 400KHz.
20 micro-sec = 8*Tclk,
Tclk = (20 micro-sec/8),
Fclk = (1/Tclk) = (8/20 micro-sec) = (8000/20)kHz = 400KHz.
Kris said:
10 years ago
f = (n/T).
f = (8/20 micro-sec).
f = 400 KHz.
f = (8/20 micro-sec).
f = 400 KHz.
Sruthi said:
1 decade ago
Because overal time delay is 20 micro secs.
For each bit 20/8 = 2.5 micro secs
In frequency it will b 400 KHZ (1/2.5 micro secs).
For each bit 20/8 = 2.5 micro secs
In frequency it will b 400 KHZ (1/2.5 micro secs).
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