Digital Electronics - Shift Registers - Discussion
Discussion Forum : Shift Registers - General Questions (Q.No. 20)
20.
If an 8-bit ring counter has an initial state 10111110, what is the state after the fourth clock pulse?
Discussion:
3 comments Page 1 of 1.
Md numan said:
6 years ago
Thanks @Nickbrar.
Nickbrar said:
1 decade ago
1. For the 1st clk pulse, it would be, 01011111
2. For the 2nd clk pulse, it would be, 10101111
3. For the 3rd clk pulse, it would be, 11010111
4. For the 4rth clk pulse, it would be, 11101011
So answer is 11101011.
2. For the 2nd clk pulse, it would be, 10101111
3. For the 3rd clk pulse, it would be, 11010111
4. For the 4rth clk pulse, it would be, 11101011
So answer is 11101011.
Ankur said:
1 decade ago
How? Can anyone explain?
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