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Digital Electronics - Shift Registers - Discussion

Discussion Forum : Shift Registers - General Questions (Q.No. 1)
Shift Registers
1.
On the fifth clock pulse, a 4-bit Johnson sequence is Q0 = 0, Q1 = 1, Q2 = 1, and Q3 = 1. On the sixth clock pulse, the sequence is ________.
Q0 = 1, Q1 = 0, Q2 = 0, Q3 = 0
Q0 = 1, Q1 = 1, Q2 = 1, Q3 = 0
Q0 = 0, Q1 = 0, Q2 = 1, Q3 = 1
Q0 = 0, Q1 = 0, Q2 = 0, Q3 = 1
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 2 of 2.
Mukesh garg said:   1 decade ago
Implemented using jk flip flop. Jhonsen counter in wch outcomes is q but bar of q is feedback to j. So sequence becomes 0111, 0011, 0001, 0000, 1000, 1100. Dere for final result is 1100.
(1)
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