Digital Electronics - Shift Registers - Discussion
Discussion Forum : Shift Registers - General Questions (Q.No. 1)
1.
On the fifth clock pulse, a 4-bit Johnson sequence is Q0 = 0, Q1 = 1, Q2 = 1, and Q3 = 1. On the sixth clock pulse, the sequence is ________.
Discussion:
11 comments Page 1 of 2.
Mukesh garg said:
1 decade ago
Implemented using jk flip flop. Jhonsen counter in wch outcomes is q but bar of q is feedback to j. So sequence becomes 0111, 0011, 0001, 0000, 1000, 1100. Dere for final result is 1100.
(1)
Bibhu said:
1 decade ago
In case of johnson counter ,the complement o/p of last ff will connect to input of fast ff.if the value is 0111,then it will produce 0011.(comp of 1 is o and that value will reflect at first)
So 0111-0011
So 0111-0011
Mona said:
1 decade ago
In case of johnson counter, the complement o/p of last ff will connect to input of fast ff. If the value 0111, then it will produce 0011.
Ex: starting value is 0000 the complement of 0 is 1 so here we will get 1000.
Ex: starting value is 0000 the complement of 0 is 1 so here we will get 1000.
Velkumargn said:
1 decade ago
IN 6th puls q3 bar is given to q0, so q0 is 0 and other 3 bits shifted right side.
Wan said:
1 decade ago
Why c? it is because the data that entered will be shift to the right.
Aru said:
1 decade ago
Why the ans is 0011.. and not 1100?
(1)
Suji said:
1 decade ago
For 0111 it is 0011, it is due to such a transition 0111.
0011. OUTPUT-the first digit remains the same and the second digit is the first digit of the input while the third digit is the second digit of the input and so on, where toggling occurs.
0011. OUTPUT-the first digit remains the same and the second digit is the first digit of the input while the third digit is the second digit of the input and so on, where toggling occurs.
Krishna said:
1 decade ago
Better to consider the flipflop for this case it is easy.
Sagar said:
9 years ago
In the case of johnson counter, the complement output of the last ff will connect to the first ff. If the value 0111, it will produce 0011.
(1)
Tamilan said:
8 years ago
Johnson counter.
Reset -- 0000
1 -- 1000
2 -- 1100
3 -- 1110
4 -- 1111
5 -- 0111
6 -- 0011
7 -- 0001
8 -- 0000
Reset -- 0000
1 -- 1000
2 -- 1100
3 -- 1110
4 -- 1111
5 -- 0111
6 -- 0011
7 -- 0001
8 -- 0000
(4)
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