Digital Electronics - Shift Registers - Discussion
Discussion Forum : Shift Registers - General Questions (Q.No. 10)
10.
In a 6-bit Johnson counter sequence there are a total of how many states, or bit patterns?
Discussion:
3 comments Page 1 of 1.
Jasbir Singh said:
1 decade ago
For a johnson counter with N number of flipflops we have 2*N output values or 2*N states will be there at output.
Pavan said:
1 decade ago
for n-bit johnson counter
total no of states or bit patterns are 2n states
for ex:n=6-bit
2n=2*6=12
total no of states or bit patterns are 2n states
for ex:n=6-bit
2n=2*6=12
Pavan said:
1 decade ago
for n-bit johnson counter
total no of states or bit patterns are 2n states
for ex:n=6-bit
2n=2*6=12
total no of states or bit patterns are 2n states
for ex:n=6-bit
2n=2*6=12
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