Digital Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - Filling the Blanks (Q.No. 38)
38.
In binary, the decimal number 93 converts to ________ digits.
Discussion:
9 comments Page 1 of 1.
Vani said:
1 decade ago
By using 8421 code its easy to understand i.e 64 32 16 8 4 2 1
1 1 0 0 0 0 0
64+32 = 96 so representing the decimal no we required seven digits.
1 1 0 0 0 0 0
64+32 = 96 so representing the decimal no we required seven digits.
Pranav said:
9 years ago
Simply, as the problem said "in binary" so divide 93 by 2 we will get digits 1011101 which equal to 7 so the answer is 7.
Ayanangshu Banerjee said:
1 decade ago
9=1001 & 3=0011 in binary.
Then how the no.of digits can be seven please explain.
Then how the no.of digits can be seven please explain.
Raj said:
1 decade ago
2^2=4, 2^5=32, 2^7=128 So that 93 is found in 2^7= 128 So ans is seven.
Faheem said:
10 years ago
93 is 1011101 in binary. So count the number of zero and one.
Joac said:
10 years ago
Please represent 93 for me in 7 bits binary.
Srisanth said:
10 years ago
I can't understand. Explain more solution?
Keerthi priya said:
1 decade ago
I can't understand this solution.
Sivakami said:
10 years ago
I can't understand. Explain more?
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