Digital Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - General Questions (Q.No. 28)
28.
Convert decimal 213 to binary.
Discussion:
2 comments Page 1 of 1.
Kahindi said:
6 years ago
Divide the decimal number i.e 213 by 2 and keep track of the remainder.
213÷2=106 rem 1
106÷2=53 rem 0
53÷2=26 rem 1
26 ÷2=13 rem 0
13 ÷2= 6 rem 1
6÷2= 3 rem 0
3÷2 =1 rem 1
1÷2=0 rem 1.
The last remainder is the most significant bit(MSB) while the first reminder the list significant bit(LSB).
Arrange the bits from MSB to the LSB and obtain the binary number which is 11010101.
213÷2=106 rem 1
106÷2=53 rem 0
53÷2=26 rem 1
26 ÷2=13 rem 0
13 ÷2= 6 rem 1
6÷2= 3 rem 0
3÷2 =1 rem 1
1÷2=0 rem 1.
The last remainder is the most significant bit(MSB) while the first reminder the list significant bit(LSB).
Arrange the bits from MSB to the LSB and obtain the binary number which is 11010101.
Kashmir chand dawer said:
9 years ago
128 = 10000000,
64 = 1000000,
32 = 100000,
16 = 10000,
8 = 1000,
4 = 100,
2 = 10,
1 = 1.
128 + 64 + 16 + 4 + 1= 213.
10000000 + 1000000 + 10000 + 100 + 1 = 11010101.
64 = 1000000,
32 = 100000,
16 = 10000,
8 = 1000,
4 = 100,
2 = 10,
1 = 1.
128 + 64 + 16 + 4 + 1= 213.
10000000 + 1000000 + 10000 + 100 + 1 = 11010101.
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