Digital Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - General Questions (Q.No. 54)
54.
Convert the Gray code 1011 to binary.
Discussion:
9 comments Page 1 of 1.
Jason said:
3 years ago
I think the right answer is 1110.
(1)
Samiksha said:
4 years ago
1011.
1+0=1,
0+1=1,
1+1=0 (carry 1).
1.
Ans obtained 1101.
1+0=1,
0+1=1,
1+1=0 (carry 1).
1.
Ans obtained 1101.
Vijayalakshmi said:
8 years ago
I can't understand this, Explain in detail.
Manjinder Singh said:
9 years ago
Answer is = 1110.
(2)
Siva said:
1 decade ago
g3 is same value of b3,
g2 is addition of g3, b2,
g1 is addition of g2, b1,
g0 is addition of g1, b0.
Above process is according to XOR GATE.
g2 is addition of g3, b2,
g1 is addition of g2, b1,
g0 is addition of g1, b0.
Above process is according to XOR GATE.
Vikas srivastava said:
1 decade ago
Lets follow a new method
I have use + sign as exor . so don't confuse
Gray code -- 1 0 1 1
g3 g2 g1 g0
Binary= b3 b2 b1 b0
g3 (b3+g2) (b2+g1) (b1+g0)
I have use + sign as exor . so don't confuse
Gray code -- 1 0 1 1
g3 g2 g1 g0
Binary= b3 b2 b1 b0
g3 (b3+g2) (b2+g1) (b1+g0)
Chandrakant said:
1 decade ago
Let g0 g1 g2 g3 = 1 0 1 1
b0 = g0 = 1
b1 = g1 xor b0 = 1
b2 = g2 xor b1 = 0
b3 = g3 xor b2 = 1
Therefore b0 b1 b2 b3 = 1 1 0 1
Hence 1101.
b0 = g0 = 1
b1 = g1 xor b0 = 1
b2 = g2 xor b1 = 0
b3 = g3 xor b2 = 1
Therefore b0 b1 b2 b3 = 1 1 0 1
Hence 1101.
Dheeraj said:
1 decade ago
How is it possible?
Sumithra said:
1 decade ago
How the answer is d?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers