Digital Electronics - Number Systems and Codes - Discussion

Discussion Forum : Number Systems and Codes - General Questions (Q.No. 6)
6.
Decode the following ASCII message.
10100111010100101010110001001011001
01000001001000100000110100101000100
STUDYHARD
STUDY HARD
stydyhard
study hard
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
47 comments Page 2 of 5.

Priya said:   8 years ago
We have to group 7 bits for each group. i.e., from least significant position to most significant position and then place them with equivalent ASCII code.

VARUN said:   1 decade ago
1010011 = 83 S 1010100 = 84 T 1010101 = 85 U 1000100 = 68 D 1011001 = 89 Y.

0100000 = 32 1001000 = 72 H 1000001 = 65 A 1010010 = 82 R 1000100 = 68 D.

Mohini said:   7 years ago
1010011 first convert to octal or hexadecimal eg. In hexadecimal, it is 53 then 53 into decimal 5*16^1 + 3*16^0=80+3=83 decimal number.

Billa said:   1 decade ago
Hey @deepika it is simple yaar. Take left side eight digits.

Eg: 01010011 this represent 53. That is the hex dec 53.

Vidhi said:   1 decade ago
We consider 8bits then 2^8.

But we have consider bits are signed bit that time only consider 2^8 bits.

Aman said:   1 decade ago
So the condition the 7 bit represented for 0000000 ?

What is ASCII CODE OF 000000, 0001010, 0000011 ?

Madhu said:   1 decade ago
Hey but according to ASCII table 53 means U, how come here they have taken S for 53 !?

Bz Abhijeet said:   10 years ago
How could we know that?

A = 65 but why not a = 65.

Please explain.

Mashewsar 9700959156 said:   1 decade ago
ASCII value for

A = 65, B = 66, ....

a = 98, b = 99, ....

Rams said:   1 decade ago
Please any one explain me, I cant understand these.


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