# Digital Electronics - Number Systems and Codes - Discussion

### Discussion :: Number Systems and Codes - General Questions (Q.No.48)

48.

What is the resultant binary of the decimal problem 49 + 01 = ?

 [A]. 01010101 [B]. 00110101 [C]. 00110010 [D]. 00110001

Explanation:

No answer description available for this question.

 Prithviraj said: (Feb 17, 2011) Simple 49+1=50 hence, 00110010 which in binary is 2^5+2^4+2^1=32+16+2=50 Hence the answer.

 Ashit said: (Jul 24, 2011) 50/2=25 0 25/2=12 1 12/2 6 0 6/2 3 0 3/2 1 1 1 110010

 B.Gopi said: (Sep 28, 2012) Simple method for binary to decimal. 49+01=50. We know coding method. 128 64 32 16 8 4 2 1 [coding method]. 0 + 0 + 1 + 1 + 0 + 0 + 1 + 0. Here. 32+16+2=50. Ans=00110010.

 Saikat said: (Oct 6, 2012) We know the coding method. 128 64 32 16 8 4 2 1. 0 + 0 +1+ 1+0+0+0+1=49. 0 0 0 0 0 0 0 1=01. By adding we get 00110010.

 Rushabh Kamdar said: (Aug 5, 2013) Last digit must be zero for even number.

 Venugopal said: (Sep 19, 2013) First we have to convert 49 into binary. i.e 49/2 = 24 1 24/2 = 12 0 12/2 = 6 0 6/2 = 3 0 3/2 = 1 1 Now binary form of 49 = 110001. Add 01 = + 01 Answer = 110010.

 New said: (Aug 24, 2015) 49+1=50. A even number hence LSB must be '0' hence option C is answer.

 Sikhumbuzo said: (Oct 9, 2017) 49=110001, 01=+01. How did add the number to be 110010?