Digital Electronics - Number Systems and Codes - Discussion

48. 

What is the resultant binary of the decimal problem 49 + 01 = ?

[A]. 01010101
[B]. 00110101
[C]. 00110010
[D]. 00110001

Answer: Option C

Explanation:

No answer description available for this question.

Prithviraj said: (Feb 17, 2011)  
Simple 49+1=50 hence, 00110010 which in binary is

2^5+2^4+2^1=32+16+2=50

Hence the answer.

Ashit said: (Jul 24, 2011)  
50/2=25 0
25/2=12 1
12/2 6 0
6/2 3 0
3/2 1 1
1
110010

B.Gopi said: (Sep 28, 2012)  
Simple method for binary to decimal.
49+01=50.
We know coding method.
128 64 32 16 8 4 2 1 [coding method].
0 + 0 + 1 + 1 + 0 + 0 + 1 + 0.
Here.
32+16+2=50.
Ans=00110010.

Saikat said: (Oct 6, 2012)  
We know the coding method.

128 64 32 16 8 4 2 1.

0 + 0 +1+ 1+0+0+0+1=49.

0 0 0 0 0 0 0 1=01.

By adding we get 00110010.

Rushabh Kamdar said: (Aug 5, 2013)  
Last digit must be zero for even number.

Venugopal said: (Sep 19, 2013)  
First we have to convert 49 into binary. i.e

49/2 = 24 1

24/2 = 12 0

12/2 = 6 0

6/2 = 3 0

3/2 = 1 1

Now binary form of 49 = 110001.

Add 01 = + 01

Answer = 110010.

New said: (Aug 24, 2015)  
49+1=50.

A even number hence LSB must be '0' hence option C is answer.

Sikhumbuzo said: (Oct 9, 2017)  
49=110001,
01=+01.

How did add the number to be 110010?

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