Digital Electronics - Multivibrators and 555 Timer - Discussion
Discussion Forum : Multivibrators and 555 Timer - General Questions (Q.No. 31)
31.
A 0.3-
F capacitor has an initial charge of 2.7 V. If it is discharged through a 10-k
resistor for 6.5 ms, how much voltage will be left across the capacitor?


Discussion:
2 comments Page 1 of 1.
Anjana said:
9 years ago
Correct @Priya.
Priya said:
1 decade ago
The voltage formula is given as Vc = V(1 - e-t/RC)
which equals: Vc = 2.7(1-e-.0065/.003) [RC = .003 seconds from above] Therefore, Vc = 2.39 volts
voltage will be left across the capacitor is 2.7V-2.39V=0.31V
which equals: Vc = 2.7(1-e-.0065/.003) [RC = .003 seconds from above] Therefore, Vc = 2.39 volts
voltage will be left across the capacitor is 2.7V-2.39V=0.31V
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