Digital Electronics - Microprocessor Fundamentals - Discussion

Discussion Forum : Microprocessor Fundamentals - General Questions (Q.No. 6)
6.
How many bits are used in the data bus?
7
8
9
16
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 1 of 2.

Tobarut said:   2 years ago
In general, a data bus is broadly defined.

The first standard for data bus was 32-bit, whereas newer 64-bit systems can handle much greater amounts of data.

Other data bus widths include 1-bit, 4-bit, 8-bit, and 16-bit.

BIKKY GUPTA said:   1 decade ago
AD0-AD7 i.e. Lower bank.
AD8-AD15 i.e. Higher bank.

So, each bank contain 8 bit. That's why 8 bit is used in data bus.
8085 - 8 bit.
8086 - 16 bit.

Anamika Pathak said:   1 decade ago
Option B is correct answer.

AD0-AD7 i.e. Lower bank.
AD8-AD15 i.e. Higher bank.

So, each bank contain 8 bit. That's why 8 bit is used in data bus.

Neha said:   1 decade ago
In 8085 up the adress & data bus are multiplexed with each other AD0-AD7, using demultiplexing i.e.latch we gwt data bits D0-D7

Suchismita mohanty said:   1 decade ago
Actually it depends upon the arrchitecture. Because for 8085 it is 8 bit, for 8086 it is 16bit.

Jigar patel said:   1 decade ago
Its depend on how many wordlength of processor. 8085 has 256 word length so databus is 8 bit.

Sukhjinder singh said:   1 decade ago
IN 8085 microproceesor data bus is 8 bit. That is why 8085 is called 8 bit microproceesor.

Deepali said:   1 decade ago
AD0-AD7 include 8 bits, where address and data are multiplexed so data is 8 bit wide.

Yaswant said:   8 years ago
In 8085, Data bus is multiplexed with address bud ie, AD0-AD7.

So 8 bits.

Rosha said:   1 decade ago
It depends on the type of processor.
8085 - 8 bit.
8086 - 16 bit.


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