Digital Electronics - Logic Gates - Discussion
Discussion Forum : Logic Gates - General Questions (Q.No. 38)
38.
If a 3-input OR gate has eight input possibilities, how many of those possibilities will result in a HIGH output?
Discussion:
5 comments Page 1 of 1.
Nithin said:
1 decade ago
In OR GATE if any input is one the output will be one and Truth table has given below for 3 inputs
000-0-->Except this input all are having output HIGH(i.e 1).
001-1.
010-1.
011-1.
100-1.
101-1.
110-1.
111-1.
So, Total -7 OUTPUT HIGH.
000-0-->Except this input all are having output HIGH(i.e 1).
001-1.
010-1.
011-1.
100-1.
101-1.
110-1.
111-1.
So, Total -7 OUTPUT HIGH.
Dinesh kumar jadon said:
1 decade ago
001 = 1
000 = 0
011 = 1
010 = 1
101 = 1
100 = 1
111= 1
110 = 1
Total = 7 high output.
000 = 0
011 = 1
010 = 1
101 = 1
100 = 1
111= 1
110 = 1
Total = 7 high output.
Anu said:
1 decade ago
Let there are three inputs a,b,c so truth table for the three input has 8 possibilties.
a b c o/p
0 0 0 0
0 0 1 1
0 1 0 1
0 1 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 1 1 1
this is the truth table for or gate
and output(o/p) of or gate is a+b+c.
a b c o/p
0 0 0 0
0 0 1 1
0 1 0 1
0 1 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 1 1 1
this is the truth table for or gate
and output(o/p) of or gate is a+b+c.
G.V.narayanan said:
1 decade ago
Explain this question. I can't understand.
Priya said:
1 decade ago
Explain?
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