Digital Electronics - Logic Gates - Discussion
Discussion Forum : Logic Gates - General Questions (Q.No. 37)
37.
A 2-input NOR gate is equivalent to a ________.
Discussion:
20 comments Page 1 of 2.
M.naresh said:
1 decade ago
Please explain me.
G.V.narayanan said:
1 decade ago
Reason for 2 input NOR gate we apply.
Why this result for AND gate?
Why this result for AND gate?
Rooh said:
1 decade ago
For input seq 00 01 10 11
output of nor is 1 0 0 0
output of and is 0 0 0 1
output of nand is 1 1 1 0
So wich is negegetive AND reffer to here i cant understand.
For me it should be negetive OR... the option A will be the answer then..
If given answer is right then please explain it to me...
output of nor is 1 0 0 0
output of and is 0 0 0 1
output of nand is 1 1 1 0
So wich is negegetive AND reffer to here i cant understand.
For me it should be negetive OR... the option A will be the answer then..
If given answer is right then please explain it to me...
Bhargavi said:
1 decade ago
Can any one please explain this clearly ?
Ashok said:
1 decade ago
Negative and gate means your inputs are inverted to the and gate. So you get a output for (00 01 10 11) is 1 0 0 0. It same as the nor gate output. Ok.
Komal said:
1 decade ago
A Negative-AND gate functions same as AND gate with all its inputs inverted
A B -A -B OR(A+B) NOR -AND(-A*-B)
0 0 1 1 0 1 1
0 1 1 0 1 0 0
1 0 0 1 1 0 0
1 1 0 0 1 0 0
From above truth table output of NOR gate and negative AND (Bubbled AND gate) are equal.
A B -A -B OR(A+B) NOR -AND(-A*-B)
0 0 1 1 0 1 1
0 1 1 0 1 0 0
1 0 0 1 1 0 0
1 1 0 0 1 0 0
From above truth table output of NOR gate and negative AND (Bubbled AND gate) are equal.
Arjun tehale said:
1 decade ago
can any one spell it out properly plz
Viswanath said:
1 decade ago
If inverter is placed for the two terminals of the and gate. Then it is nor gate. Then from this we can say that -ve and gate is equivalent to nor gate.
Khyati said:
1 decade ago
If we compare truth table of negative AND gate And truth table of NOR gate. Than we can easily understand.
GURUSWAMY said:
1 decade ago
Given inputs are A, B,
Case 1:
For NOR gate output is (A+B)complement.
Case 2 :
For negative and gate output is:
(A complement) * (B complement) = (A+B) complement.
Case 1:
For NOR gate output is (A+B)complement.
Case 2 :
For negative and gate output is:
(A complement) * (B complement) = (A+B) complement.
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