Digital Electronics - Logic Families and Their Characteristics - Discussion
Discussion Forum : Logic Families and Their Characteristics - General Questions (Q.No. 6)
6.
Assume that a particular IC has a supply voltage (Vcc) equal to +5 V and ICCH = 10 mA and ICCL = 23 mA. What is the power dissipation for the chip?
Discussion:
4 comments Page 1 of 1.
Archu said:
5 years ago
Icc= 10+23/2= 16.5mA,
Ppd=Vcc*Icc,
Pdp=16.5*5=82.5mW.
Ppd=Vcc*Icc,
Pdp=16.5*5=82.5mW.
Akanksha said:
8 years ago
Icc=IccH+IccL/2.
Icc=(10+23)/2.
=33/2.
=16.5.
Power dissipation =Icc*Vcc.
=16.5*5.
=82.5.
Icc=(10+23)/2.
=33/2.
=16.5.
Power dissipation =Icc*Vcc.
=16.5*5.
=82.5.
Komal said:
1 decade ago
Icc = (10+23)/2 =16.5 mA
power = Voltage * Current
= Vcc * Icc
= 16.5 * 5
= 82.5 mW
power = Voltage * Current
= Vcc * Icc
= 16.5 * 5
= 82.5 mW
OBULESU said:
1 decade ago
P=(Vcc*Icc)
and Icc=(Icch+Iccl)/2
and Icc=(Icch+Iccl)/2
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