Digital Electronics - Integrated Circuit Technologies - Discussion

Discussion :: Integrated Circuit Technologies - General Questions (Q.No.20)

20. 

A certain gate draws 1.8 A when its output is HIGH and 3.3 µA when its output is LOW. VCC is 5 V and the gate is operated on a 50% duty cycle. What is the average power dissipation (PD)?

[A]. 2.55 W
[B]. 1.27 W
[C]. 12.75 W
[D]. 5 W

Answer: Option C

Explanation:

No answer description available for this question.

Pavani said: (Aug 23, 2011)  
Pd=Vcc*Icc(avg)
Icc(avg)=ICCH+ICCL/2
Pd=5*(1.8+3.3)/2=12.75

Praveen said: (May 30, 2017)  
Yes, your Explanation is correct. Thanks @Pavani.

Ahmed said: (May 17, 2018)  
What is the answer, If duty cycle 35%?

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