Digital Electronics - Digital Signal Processing - Discussion
Discussion Forum : Digital Signal Processing - Filling the Blanks (Q.No. 10)
10.
Assume that in a certain 4-bit weighted ladder DAC, the input representing the most significant bit is applied to a 20 k
resistor. What is the size of the resistor that represents the least significant bit?
resistor. What is the size of the resistor that represents the least significant bit?2.5 k
5 k
80 k
160 k
Discussion:
2 comments Page 1 of 1.
Sourabh Nath said:
1 decade ago
The opamp configuration of weighted resistor gives V=Rf(V2/R2+V1/R1+V0/R0) where conventionally R0=8k, R1=4k and R2=2k and Rf=1k.
Thus for Rf=20k, R0(concerned with LSB)=20*8k=160k.
Thus for Rf=20k, R0(concerned with LSB)=20*8k=160k.
Gopi said:
1 decade ago
R = 20;
2R = 40;
4*2R = 160
2R = 40;
4*2R = 160
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