Digital Electronics - Digital Signal Processing - Discussion
Discussion Forum : Digital Signal Processing - General Questions (Q.No. 4)
4.
For a 4-bit DAC, the least significant bit (LSB) is ________.
Discussion:
9 comments Page 1 of 1.
Preetha said:
1 decade ago
N=4-bit
LSB= (1/2^n)*100
=(1/2^4)*100
=(1/16)*100
=0.0625*100
=6.25
LSB= (1/2^n)*100
=(1/2^4)*100
=(1/16)*100
=0.0625*100
=6.25
(6)
Monica said:
9 years ago
For LSB , (1/2^n) * 100.
Then what is for MSB?
Then what is for MSB?
(2)
Chithraseenivasan said:
8 years ago
Thank you @Preetha. It is Easily understood.
Vishal said:
8 years ago
Really helpful. Thanks for the explanation.
Kalakal said:
10 years ago
Super Preetha, easily I can understand it.
Sandhiya said:
10 years ago
Thanks for your explanation @Preetha.
Pankaj said:
1 decade ago
Good answer preetha.
(1)
Swetha M said:
9 years ago
Thank you @Preetha.
Latha said:
1 decade ago
Thank you preetha.
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