Digital Electronics - Digital Signal Processing - Discussion
Discussion Forum : Digital Signal Processing - General Questions (Q.No. 7)
7.
In a digital representation of voltages using an 8-bit binary code, how many values can be defined?
Discussion:
5 comments Page 1 of 1.
Kiran shettar said:
1 decade ago
2^8=256
Prabhakaran S said:
1 decade ago
With 8-bits the no. of possible values are 2^8=256.
Mohd.aamir sheikh said:
1 decade ago
Since the base of the binary number system is 2
and it is said that in digital representation of voltages we need to show in 8-bit binary code
So,2 to the power 8 will be the answer........
i.e, 2^8=256
(or 2*2*2*2*2*2*2*2=256)
and it is said that in digital representation of voltages we need to show in 8-bit binary code
So,2 to the power 8 will be the answer........
i.e, 2^8=256
(or 2*2*2*2*2*2*2*2=256)
Akhilesh Iyer said:
10 years ago
That seems to be quite the thing.
That is, if there are 8 bits in the signal and there are 2 possible representations of voltage levels in a binary number system. Then every bit has the possibility of being represented by any of those 2 numbers.
Hence, 2*2*2*2*2*2*2*2 = 2^8 = 256.
That was some explanation.
That is, if there are 8 bits in the signal and there are 2 possible representations of voltage levels in a binary number system. Then every bit has the possibility of being represented by any of those 2 numbers.
Hence, 2*2*2*2*2*2*2*2 = 2^8 = 256.
That was some explanation.
Rajkumar Patel said:
7 years ago
2^8 = 256.
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