Digital Electronics - Digital Concepts - Discussion
Discussion Forum : Digital Concepts - General Questions (Q.No. 42)
42.
A periodic digital waveform has a pulse width (tw) of 6 ms and a period (T) of 18 ms. The duty cycle is ________.
Discussion:
12 comments Page 1 of 2.
Raj said:
1 decade ago
D = T/P*100 %.
Where D is the duty cycle, T is the time the signal is active, and P is the total period of the signal.
D = 6ms/18ms*100 {where milli = 10^-3}.
So, D = (6x10^-3)/(18x10^-3)*100.
= (6/18)*(10^-3/10^-3)*100.
= 1/3*100.
= 33.3% HP.
Where D is the duty cycle, T is the time the signal is active, and P is the total period of the signal.
D = 6ms/18ms*100 {where milli = 10^-3}.
So, D = (6x10^-3)/(18x10^-3)*100.
= (6/18)*(10^-3/10^-3)*100.
= 1/3*100.
= 33.3% HP.
(1)
Paresh said:
1 decade ago
But both are in ms than why convert its to second than upper side also we can multiply by 100 ?
Answer was right but I can't understand please.
Answer was right but I can't understand please.
Ramakishor mutyala said:
1 decade ago
Duty cycle is defined as pulse width(PW) divided by pulse repitition time(PRT)
Duty cycle = PW/PRT
Duty cycle = PW/PRT
Shyam verma said:
1 decade ago
D = ton/total time period.
Ton = 6 ms.
Total time period = 18 ms.
6/18*100 = 33.33%.
Ton = 6 ms.
Total time period = 18 ms.
6/18*100 = 33.33%.
Appu said:
1 decade ago
D=ton/total time period
ton=6ms
total time period=18ms
so in percentage 33.33%
ton=6ms
total time period=18ms
so in percentage 33.33%
Anji said:
1 decade ago
PW is pulse width and PRT is pulse repetition time i.e., total period.
Raviprakash G Mishra said:
7 years ago
The Duty Cycle =Ton/(Ton+Toff) that is;
6ms/18ms,
= 33.3%.
6ms/18ms,
= 33.3%.
(1)
Amit said:
1 decade ago
Duty cycle can define in % then we multiply.
Dipti said:
1 decade ago
what is pw and prt please mention.
Raviraj said:
1 decade ago
Because it is in percentage.
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