Digital Electronics - Digital Concepts - Discussion
Discussion Forum : Digital Concepts - General Questions (Q.No. 41)
41.
How many binary bits are necessary to represent 748 different numbers?
Discussion:
19 comments Page 1 of 2.
Murugan said:
1 decade ago
@Priyank is right but I think that raj method of identification is wrong because, how this is right== 7 (111) , 4 (100) , 8 (1000) total of 10 bits.
i.e. (1111001000) mark from LSB Then you feel the answer is wrong if you separate in hexadecimal then you have to separate by four bits then 0011 1100 1000==3c8. This is wrong answer. Any correction please reply.
i.e. (1111001000) mark from LSB Then you feel the answer is wrong if you separate in hexadecimal then you have to separate by four bits then 0011 1100 1000==3c8. This is wrong answer. Any correction please reply.
Priyank said:
1 decade ago
748/2= div-374 rem=0
374/2= div-187 rem=0
187/2= div-93 rem=1
93/2= div-46 rem=1
46/2 div-23 rem=0
23/2 div-11 rem=1
11/2 div-5 rem=1
5/2 div-2 rem=1
2/2 div-1 rem=0
1/2 div=0 rem=1
Hence (748)=1011101100
So 10 digits are required to represent 748.
374/2= div-187 rem=0
187/2= div-93 rem=1
93/2= div-46 rem=1
46/2 div-23 rem=0
23/2 div-11 rem=1
11/2 div-5 rem=1
5/2 div-2 rem=1
2/2 div-1 rem=0
1/2 div=0 rem=1
Hence (748)=1011101100
So 10 digits are required to represent 748.
(5)
Sirisha said:
1 decade ago
Agreeing with @Murugan.
Example: Take 99.
If 9(1001),9(1001) total of 8 bits.
But 99=1100011, see 7 bits are enough.
@Raji method of identification is wrong.
Example: Take 99.
If 9(1001),9(1001) total of 8 bits.
But 99=1100011, see 7 bits are enough.
@Raji method of identification is wrong.
Panchakshari S H M said:
2 years ago
For 8 all 1's means it is 255,
For 7 all 1's means it is 127,
For 9 all 1's mean it is 511,
For 10 all 1's means, it is 1023.
So, the answer is 10.
For 7 all 1's means it is 127,
For 9 all 1's mean it is 511,
For 10 all 1's means, it is 1023.
So, the answer is 10.
(1)
Vinsan@hyderabad said:
1 decade ago
748= 512 + 0 + 128 + 64 + 32 + 0 + 8 + 4 + 0 +0(2 powers in order)
748= 10 1110 1100 Total ten bits required to represent 748 numbers
748= 10 1110 1100 Total ten bits required to represent 748 numbers
Raji said:
1 decade ago
By using 8-4-2-1 method also we can find it..
like binary number of 7(111),4(100), 8(1000) total of 10 bits.. i.e(1111001000)
like binary number of 7(111),4(100), 8(1000) total of 10 bits.. i.e(1111001000)
Papu said:
1 decade ago
2^9=512 that means we can write at most 512 with 9 digits.
2^19=1024 that means we can represent up to 1024 with 10 digits.
2^19=1024 that means we can represent up to 1024 with 10 digits.
Nisha said:
9 years ago
@Priyank. You are correct because it is very easy to understand these binary to decimal conversion method.
SHAIK MOULALI said:
1 decade ago
Thank you raji. That's quite easy method. Will it hold correct for similar question with different value.
Supraja said:
1 decade ago
Thank you raji. Thats quite easy method. Will it hold correct for similar question with different value.
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