Digital Electronics - Digital Concepts - Discussion
Discussion Forum : Digital Concepts - General Questions (Q.No. 47)
47.
The frequency of a pulse train is 2 kHz. The pulse period is ________.
5 ms
50 ms
500 
s
s2 s
sDiscussion:
8 comments Page 1 of 1.
Mahesh said:
9 years ago
t = 1/2000,
t = 0.0005;
t = 5 * 10^-4;
t = 500 * 10^-6;
t = 500 μs.
t = 0.0005;
t = 5 * 10^-4;
t = 500 * 10^-6;
t = 500 μs.
(2)
Manikandan said:
9 years ago
T = 1/F.
So 2 * 0.001 = 0.002.
1/0.002 = 500.
So 2 * 0.001 = 0.002.
1/0.002 = 500.
Viji said:
9 years ago
No, because KHZ is 10^3.
Thirupathi said:
9 years ago
t = 1/f,
t = 1/2k.
t= 1000/2.
t = 500.
Am I right?
t = 1/2k.
t= 1000/2.
t = 500.
Am I right?
(1)
Saminathan said:
1 decade ago
Let describe the formula
1000/MHz= ns
1000/KHz= micro second
1000/Hz= milli second
Answer: 1000/2 KHz= 500 micro second
1000/MHz= ns
1000/KHz= micro second
1000/Hz= milli second
Answer: 1000/2 KHz= 500 micro second
(2)
Ahi said:
1 decade ago
t=1/f
so t=1/2*10^3
then t=10^-3/2
=10^-3*0.5
=500*10-6
=500us
so t=1/2*10^3
then t=10^-3/2
=10^-3*0.5
=500*10-6
=500us
Vishnuvarthan.L said:
1 decade ago
Because of time is indirectly proportional to the frequency so that
(Time period) T = 1/f(frequency)
(Time period) T = 1/f(frequency)
Aquib jamal said:
1 decade ago
Time period T = 1/(frequency)
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