Digital Electronics - Digital Arithmetic Operations and Circuits - Discussion
Discussion Forum : Digital Arithmetic Operations and Circuits - General Questions (Q.No. 48)
48.
How many BCD adders would be required to add the numbers 97310 + 3910?
Discussion:
2 comments Page 1 of 1.
Shabina said:
1 decade ago
Firstly write BCD code for 973
i.e 1001 0111 0011
BCD code for 39
i.e 0011 1001
Add both binary no's. i.e 1001 1010 1100
> than 9. so add 6 BCD code
Now result 1010 0001 0010
Again > 9. add 6
00001 0000 0001 0010 is finally our result,
Thus 3 times BCD adder used.
i.e 1001 0111 0011
BCD code for 39
i.e 0011 1001
Add both binary no's. i.e 1001 1010 1100
> than 9. so add 6 BCD code
Now result 1010 0001 0010
Again > 9. add 6
00001 0000 0001 0010 is finally our result,
Thus 3 times BCD adder used.
Priya said:
8 years ago
As per no of count, you are right @Shabina.
But question requires how many bad adders. Please elaborate it.
But question requires how many bad adders. Please elaborate it.
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