Digital Electronics - Digital Arithmetic Operations and Circuits - Discussion
Discussion Forum : Digital Arithmetic Operations and Circuits - General Questions (Q.No. 46)
46.
Convert the decimal numbers 275 and 965 to binary-coded decimal (BCD) and add. Select the BCD code groups that reflect the final answer.
Discussion:
4 comments Page 1 of 1.
KIRAN V said:
5 years ago
275 --> 0010 0111 0101
975 --> 1001 0111 0101
--------------------------------
1240--> 1011 1101 1010.
In BCD more than 1001 (>9), the number is INVALID, for Correction we need to ADD 0110 to each BCD No.
1011 1101 1010
0110 0110 0110
----------------------
1001001000000
Group the Final Ans in 4-bits each and for MSB 1 - append Three 0's at left. ie. 0001 0010 0100 0000 ==> In Decimal form ==> 1240.
975 --> 1001 0111 0101
--------------------------------
1240--> 1011 1101 1010.
In BCD more than 1001 (>9), the number is INVALID, for Correction we need to ADD 0110 to each BCD No.
1011 1101 1010
0110 0110 0110
----------------------
1001001000000
Group the Final Ans in 4-bits each and for MSB 1 - append Three 0's at left. ie. 0001 0010 0100 0000 ==> In Decimal form ==> 1240.
Lan said:
10 years ago
275 + 965 = 1240. Convert it into BCD then we get 0001 0010 0100 0000.
Mrece said:
1 decade ago
I agree with you. Can someone show other solution?
Somasekhar said:
1 decade ago
I think here getting different answers for BCD addition which method here following I can't understand.
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