Digital Electronics - Digital Arithmetic Operations and Circuits - Discussion

3. 

Perform subtraction on each of the following binary numbers by taking the two's-complement of the number being subtracted and then adding it to the first number.
01001        01100
00011        00111

[A]. 01100    10011
[B]. 00110    00101
[C]. 10110    10101
[D]. 00111    00100

Answer: Option B

Explanation:

No answer description available for this question.

Pavani said: (Aug 10, 2011)  
Take given data in the form of a, b then

BCD subtraction= a+(9'scomplement of b) we get ans >9 then add 6 to the ans after msb is 1 that carry is added to the ans

Given a=01001,b=00011
a+b=0110+1001=1111>9
1111+0110=1101
0101+1=00110

Bala said: (Jun 16, 2015)  
Given:

1) 011001.
00011-->2's complement =11101. Add with 011001 we will get 00110.

2) 01100.
00111--->2's complement =11001. Add with 01100 we will get 00101.

So answer is B 00110 00101.

Shiv Babu Kushwaha said: (Sep 25, 2015)  
When we are subtracting any binary no using 2's compliment attention on it.

Take binary no, which we want to subtract.

Ex. A-B = (110011)-(011011).

Take B = 011011.

Find out 2's compliment of B.

First find 1's compliment as convert it as '1' becomes 0 and '0' becomes 1.

1's compliment is B = 100100.

Add 1 on LSB with 1's compliment.

2's compliment is B' = 100100.

+1.

B' = 100101.

Then A+B' = 110011+100101.

= 011000 this is our answer.

Kiran V said: (Aug 20, 2020)  
Given:

01001 ->01001 -> 01001.

00011-> 1's Complement 11100.
And 2's Complement -> 11101.
Add Both the Numbers i.e 100110.

Ignore the MSB then we will get -> 00110.

Similarly,

01100 ->01100-> 01100.

00111 -> 1's Complement 11000
And 2's Complement ->11001
Add Both the Numbers i.e 100101.

And finally, we get -> 00101.

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