Digital Electronics - Digital Arithmetic Operations and Circuits - Discussion
Discussion Forum : Digital Arithmetic Operations and Circuits - General Questions (Q.No. 5)
5.
Multiply the following binary numbers.
| 1010 | 1011 | 1001 | ||
| ×0011 | ×0111 | ×1010 |
Discussion:
5 comments Page 1 of 1.
Anubhav said:
4 years ago
0b1010 = 0xA.
0b0011 = 0x3.
0xA * 0x3 = 0x1E = 0b00011110.
0b1011 = 0xB.
0b0111 = 0x7.
0xB * 0x7 = 0x4D = 0b01001101.
0b1001 = 0x9.
0b1010 = 0xA.
0x9 * 0xA = 0x5A = 0b01011010.
0b0011 = 0x3.
0xA * 0x3 = 0x1E = 0b00011110.
0b1011 = 0xB.
0b0111 = 0x7.
0xB * 0x7 = 0x4D = 0b01001101.
0b1001 = 0x9.
0b1010 = 0xA.
0x9 * 0xA = 0x5A = 0b01011010.
Vishnu said:
8 years ago
Thank you @Geeta.
(1)
Geeta said:
1 decade ago
1010 *0011=10*3=30=0001 1110
1011 *0111=11*7=77=0100 1101
1001 *1010=9*10=90=0101 1010
so ans is c
=0001 1110 0100 1101 0101 1010
1011 *0111=11*7=77=0100 1101
1001 *1010=9*10=90=0101 1010
so ans is c
=0001 1110 0100 1101 0101 1010
MANISH said:
1 decade ago
ANS. C
SOLUTION;
1010 1011 1001
*0011 *0111 *1010
=0001 1110 =0100 1101 =0101 1010
SOLUTION;
1010 1011 1001
*0011 *0111 *1010
=0001 1110 =0100 1101 =0101 1010
Malleswararao said:
1 decade ago
Please give answers with solutions.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers