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Digital Electronics - Digital Arithmetic Operations and Circuits - Discussion

Discussion Forum : Digital Arithmetic Operations and Circuits - General Questions (Q.No. 8)
Digital Arithmetic Operations and Circuits
8.
Solve this BCD problem: 0100 + 0110 =
00010000BCD
00010111BCD
00001011BCD
00010011BCD
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.
Manish said:   1 decade ago
0100+0110=1010 in BCD addition (greater than 9 add 0110)
1010+0110=0001 0000
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