Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 14)
14.
A MOD-12 and a MOD-10 counter are cascaded. Determine the output frequency if the input clock frequency is 60 MHz.
Discussion:
5 comments Page 1 of 1.
KIRAN V said:
5 years ago
If two counters are cascaded with MOD-M followed by MOD-N, then combined counter is (M x N) and counter is called" MOD (M x N)" counter.
Output frequency = fin/ (M x N).
Output frequency (fout) = (60 * 106) / (12 * 10).
Output frequency (fout) = 500 KHz.
Output frequency = fin/ (M x N).
Output frequency (fout) = (60 * 106) / (12 * 10).
Output frequency (fout) = 500 KHz.
Adesh Paul said:
6 years ago
If two counters are cascaded with MOD-M followed by MOD-M, then combined counter is (M x N) and counter is called"MOD-MN" counter.
Output frequency = f/MxN.
Output frequency = f/MxN.
Shashank said:
8 years ago
Total count 120.
This requires 7ff,
So freq=60/(2^7)=468.75khz.
This requires 7ff,
So freq=60/(2^7)=468.75khz.
Vishal Deshraj said:
1 decade ago
For MOD 12:-
Frequency will be divided as=60mHz /12=5 MHz
than For MOD 10:-
Again frequency division
5 MHz /10=500kHz
Frequency will be divided as=60mHz /12=5 MHz
than For MOD 10:-
Again frequency division
5 MHz /10=500kHz
Sreekala.k.s said:
1 decade ago
Total mod=12 x 10 =120
So output frequency = 60 Mhz /120 =500k
So output frequency = 60 Mhz /120 =500k
(2)
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