Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 11)
11.
The simplest equation which implements the K-map shown below is:
Discussion:
11 comments Page 1 of 2.
Chandan Pahuja said:
1 decade ago
Using k map the upper four 1's make a quad which gives expressions B and the remaining 1 make doublet with its upper 1 which gives expression AC.
We are solving this kmap by assuming sop form. So output will be sum of both expression i.e. B+AC.
We are solving this kmap by assuming sop form. So output will be sum of both expression i.e. B+AC.
Swathi said:
9 years ago
(A bar B C bar)+ (A bar B C)+ (A B C bar) + (A B C)+ (A B bar C).
(A bar B(C+ C bar)+ A B (C bar + C)+ (A B bar C).
(A bar B) + (A B) + (A B bar C).
B (A bar + A) + (A B bar C).
B + (A B bar C).
AC (B + B bar).
Ans = AC.
(A bar B(C+ C bar)+ A B (C bar + C)+ (A B bar C).
(A bar B) + (A B) + (A B bar C).
B (A bar + A) + (A B bar C).
B + (A B bar C).
AC (B + B bar).
Ans = AC.
Hiba said:
8 years ago
Hi, everyone.
I just want to know how can we make this equation with as much as needed of XOR, NOT and only one OR and tks in advance?
The equation : E= ABC+B'C'+A'B'+A'C'.
note : the (') means negation.
I just want to know how can we make this equation with as much as needed of XOR, NOT and only one OR and tks in advance?
The equation : E= ABC+B'C'+A'B'+A'C'.
note : the (') means negation.
Dhasaratharaman said:
8 years ago
(A bar B C bar)+ (A bar B C)+ (A B C bar) + (A B C)+ (A B bar C).
(A bar B(C+ C bar)+ A B (C bar + C)+ (A B bar C).
(A bar B) + (A B) + (A B bar C).
B (A bar + A) + (A B bar C).
B + (A B bar C).
(A bar B(C+ C bar)+ A B (C bar + C)+ (A B bar C).
(A bar B) + (A B) + (A B bar C).
B (A bar + A) + (A B bar C).
B + (A B bar C).
(1)
MAHI said:
7 years ago
By formula: A+A^B=A+B.
Likewise after combining;
11
11
and 1
we will get the below equation.
B+AB^C.
which can be simplified as;
B+AB^C=AC+B.
Likewise after combining;
11
11
and 1
we will get the below equation.
B+AB^C.
which can be simplified as;
B+AB^C=AC+B.
Seetha said:
6 years ago
Change to this format:
0 0 1 1
0 1 1 1
Tthen pair the 1(using kmap).
Then the answer is = B+AC.
0 0 1 1
0 1 1 1
Tthen pair the 1(using kmap).
Then the answer is = B+AC.
Viki said:
9 years ago
B +A B(bar) C= B + A.B + B(bar).B+C => B + A.B + C = B(A+C) then how it's ?
Arjun said:
1 decade ago
Rashmi said correct..............
Preethi said:
1 decade ago
How can you explain me ?
Suraj said:
7 years ago
What is k map?
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