Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 5)
5.
For the device shown here, let all D inputs be LOW, both S inputs be HIGH, and the 
input be HIGH. What is the status of the Y output?
Discussion:
29 comments Page 2 of 3.
Arshid Bhat said:
7 years ago
@All.
Multiplexer only works when (enable is low), as Here enable is high that means multiplexer is not working, so the output is low.
Multiplexer only works when (enable is low), as Here enable is high that means multiplexer is not working, so the output is low.
Ujjal said:
9 years ago
When ENABLE input is high, which means to disable the device.
So, Output may go into High Impedance, and the answer is option D.
So, Output may go into High Impedance, and the answer is option D.
Vinay said:
9 years ago
As given input not able to enable the mux so it has any previous value either low or high, so according to me, its don't care.
Hagos said:
1 decade ago
Yes, I agree with you @Zion, because if the device is not working means its out put is low. So the answer is LOW.
Hari said:
1 decade ago
Without enabling the ic how can it gives the output. I am against the answer. If I am wrong then suggest me.
Dokhe said:
9 years ago
Because the D input out do the S input so the answer can be A, though the input is not enabled.
Nagesh said:
8 years ago
Answer is A.
Because when enable is low, the circuit will be disabled, so output will be low.
Because when enable is low, the circuit will be disabled, so output will be low.
GHC said:
9 years ago
Here, the device is not be enabled and MUX not enabled will give an output of logic 0 (low).
Aggression said:
10 years ago
If the device is not enabled, it should go in high impedance state which is denoted by "Z".
Zion said:
1 decade ago
The device is "Not enable". NOT ENABLE = 0, 0=low. The answer is LOW.
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