Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 7)
7.
A 74HC147 priority encoder has ten active-LOW inputs and four active-LOW outputs. What would be the state of the four outputs if inputs 4 and 5 are LOW and all other inputs are HIGH?
Discussion:
16 comments Page 1 of 2.
Baz said:
7 years ago
This is wrong the answer should be C because with 0101 the LSB is A0 and MSB is A3 the answer A is technically 1010 which is a decimal 10.
(1)
Bijendra Kumar said:
1 decade ago
As two Inputs are low, I4 is given priority(5th i/p), so respective o/p 0101 represents 5. So, it is the correct answer.
B kaur said:
1 decade ago
But what is meant by active-low outputs here?
Vishal rana said:
1 decade ago
Active low means when logic is 0 apply then it is consider 1.
(high) & vice verse.
(high) & vice verse.
Radha said:
1 decade ago
Can you explain clearly how priority is assigned.
Diya said:
1 decade ago
Could you please explain active low OUTPUT here?
Macky said:
10 years ago
I'm confuse about the active low output, please explain.
Nehal said:
10 years ago
It means it will be active when output is low (=0). Only then it shows us the output.
Bunty said:
10 years ago
Please explain this question elaborately.
Rglokkesh said:
9 years ago
Active high inputs mean the input goes high if it is open, and requires the previous stage driving the input to sink current in the low state to pull the input low to from a logical zero.
The active low output means that the output in the low state can sink current.
The active high output means that the output can source current in the high state.
All TTL parts are active high input and active low output.
The active low output means that the output in the low state can sink current.
The active high output means that the output can source current in the high state.
All TTL parts are active high input and active low output.
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