Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 12)
12.
How many 1-of-16 decoders are required for decoding a 7-bit binary number?
Discussion:
11 comments Page 1 of 2.
Durga said:
7 months ago
The input is a 7-bit binary number.
So for 7 inputs, we have 2^7 OUTPUT which means 128 outputs,
Here we have a 1^16 decoder we have 16 outputs here,
So 128/16 = 8.
So, the answer is 8.
So for 7 inputs, we have 2^7 OUTPUT which means 128 outputs,
Here we have a 1^16 decoder we have 16 outputs here,
So 128/16 = 8.
So, the answer is 8.
(1)
Selva said:
7 years ago
The Number of decoders which are used only 9.
We need 1 to 16 decoders of 8 and the 3 to 8 decoders of 1. So total 9.
They have asked 1 to 16 decoders so 8.
The input lines is 7 and the output line is 128.
we are having 1 to 16 decoder so 128/16 =8.
And another one for enabling all the 8 decoders. So, we want 3 to 8 decoder.
We need 1 to 16 decoders of 8 and the 3 to 8 decoders of 1. So total 9.
They have asked 1 to 16 decoders so 8.
The input lines is 7 and the output line is 128.
we are having 1 to 16 decoder so 128/16 =8.
And another one for enabling all the 8 decoders. So, we want 3 to 8 decoder.
Mahi said:
7 years ago
It means1 Input 16 Outputs.
Naresh said:
8 years ago
What does it mean by 1 of 16 decoders? Please explain in detail.
Sanchali Dutta said:
8 years ago
What does 1 of 16 decoder means?
Lakshmi said:
8 years ago
Please explain me.
Sam said:
8 years ago
What does it mean by 1 of 16 decoders?
Please explain me.
Please explain me.
Ravi Raj said:
1 decade ago
How are we going to connect the i/p lines.
Let us say the binary no. is A6...A0.
A3...A0 are common to all decoders but what about the remaining A6...A4. How are going to use them.
I guess there should be one more option of 9 decoders to use last 3 bits as enable lines for the 8 decoders.
But in this case how are going to connect them ?
Let us say the binary no. is A6...A0.
A3...A0 are common to all decoders but what about the remaining A6...A4. How are going to use them.
I guess there should be one more option of 9 decoders to use last 3 bits as enable lines for the 8 decoders.
But in this case how are going to connect them ?
(1)
Ran said:
1 decade ago
@Ram,
7 bit means 2^7 combinations i.e 128. So to decode 128 combinations we require 128/16=8 1 of 16 decoders.
7 bit means 2^7 combinations i.e 128. So to decode 128 combinations we require 128/16=8 1 of 16 decoders.
(2)
Ram said:
1 decade ago
@Samir.
Can you please explain the theory behind the calculation ?
Can you please explain the theory behind the calculation ?
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