Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 39)
39.
How many 4-bit parallel adders would be required to add two binary numbers each representing decimal numbers up through 30010?
Discussion:
4 comments Page 1 of 1.
Chaithu said:
5 years ago
Total 9 digits, in 4 bit adder we got inputs b3b2b1b0 and a3a2a1a0, we need a8a7. A0 for 9 digits, and with 2 adders, we will get upto a7. A0, for a8 we need another adder.
(2)
Vamsi said:
7 years ago
Total 9 bits, 4 bit parallel adders.
9bits/4bits.
9bits/4bits.
Sanskriti said:
7 years ago
@Jaxtis.
How we got 9/4?
How we got 9/4?
Jaxtis said:
1 decade ago
300 = 100101100 (Binary).
Total number of digits == 9.
9/4 is greater than 2 and less than 4, so obviously 3.
Total number of digits == 9.
9/4 is greater than 2 and less than 4, so obviously 3.
(4)
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