Digital Electronics - Combinational Logic Analysis - Discussion
Discussion Forum : Combinational Logic Analysis - General Questions (Q.No. 11)
11.
To implement the expression 
, it takes one OR gate and ________.
, it takes one OR gate and ________.Discussion:
5 comments Page 1 of 1.
Narayan said:
1 year ago
Thanks for explaining the answer @Jeya.
Sadeg said:
5 years ago
Here; the explanation is;
>> AB'CD > one And Gate and invert to B.
>> ABC'D > one And Gate and invert to C.
>> ABCD' > one And Gate and invert to D.
>> AB'CD > one And Gate and invert to B.
>> ABC'D > one And Gate and invert to C.
>> ABCD' > one And Gate and invert to D.
(1)
Denish kyada said:
6 years ago
Please, Explain it in detail.
Jeya said:
1 decade ago
The expression is AB'CD + ABC'D + ABCD'.
AND gate-I is for the expression AB'CD;inverter-1 is connected to i/p B.
AND gate-II is for the expression ABC'D;inverter-2 is connected to i/p C.
AND gate-III is for the expression ABCD';inverter-3 is connected to i/p D.
For adding all these 3 expressions ,V need one OR gate.
So totally the expression needs 3 AND gate, 3 inverters, 1 OR gate.
AND gate-I is for the expression AB'CD;inverter-1 is connected to i/p B.
AND gate-II is for the expression ABC'D;inverter-2 is connected to i/p C.
AND gate-III is for the expression ABCD';inverter-3 is connected to i/p D.
For adding all these 3 expressions ,V need one OR gate.
So totally the expression needs 3 AND gate, 3 inverters, 1 OR gate.
(1)
Kavi said:
1 decade ago
Explain it. I don't know.
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