Discussion :: Combinational Logic Analysis - General Questions (Q.No.5)
Implementing the expression AB + CDE using NAND logic, we get:
Answer: Option A
No answer description available for this question.
|Amit Kumar said: (Mar 3, 2015)|
|Answer is C because only OR gate can perform + operation.|
|Priya said: (May 21, 2015)|
|Any one can explain me?|
|Jai said: (Sep 26, 2015)|
|But there is answer A? Is right or wrong?|
|Md Nazim said: (Oct 5, 2015)|
|Bubble at the end of and gate and bubble at the starting of or gate will cancel each other so A is correct answer. Because 1st and gate will give ab and 2nd and gate will give cde and or gate taking input 1st input=ab, 2nd input=cde will give the result ab+cde.|
|Gaurav Chavda said: (Sep 4, 2016)|
|A is the correct answer. Continuous 2 bubble cancels each other. So circuit in option A is simple to implement AB + CDE.|
|Vineet said: (Jan 22, 2018)|
|First of all, "read" the question. They asks using NAND gate. So option c having OR gate is canceled out, option D having AND gate also cancel out, now there are A and B. We are to find first AB we see option A has AB. So, accurately answer is A.|
|Rohit said: (May 17, 2018)|
|I am not understanding this. Please explain.|
|Asharaf Ansari said: (Dec 7, 2018)|
|No, we have to use only NAND gates.|
|Paul said: (Jun 17, 2019)|
|Yes, A is correct.
(A+B)' + (CDE)' = from the output of NAN Gates.
(A+B)+(CDE) = to the input of OR gate.
|Raji Oruganti said: (Jun 4, 2020)|
|A is correct answer as per rule A"=A.
|Kranti said: (Jul 6, 2020)|
|The bubbled OR gate is equivalent to NAND gate, so(ab* (.)cde*)*= ab + cde.|
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