Digital Electronics - Boolean Algebra and Logic Simplification - Discussion

Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 28)
28.
A Karnaugh map is a systematic way of reducing which type of expression?
product-of-sums
exclusive NOR
sum-of-products
those with overbars
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

A j kiran said:   8 years ago
Both (sop & pos) both are used,

But sop is most likely to be use.
(1)

Susheel kumar said:   1 decade ago
I think by using k-map we can easily to simplify Boolean expressions whether (sop and pos).

Antara bhattacharjee said:   1 decade ago
By using k-map we can solve both s-o-p & p-o-s form.
(1)

Abhishek srivastava said:   1 decade ago
We can directly plot pos no conversion is required directly from truth table. Simplify just top and side expressions; converted to respective pos for eg:A'B' becomes A+B and just take 0's from truth table And plot And simplify as usual.

Bobby said:   1 decade ago
[A] is also a correct answer

Ruvathya said:   1 decade ago
Sop form can only be implemented easily. If it s not in sop form (pop) then yo have to convert it into sop then use k map to reduce it further.

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