Digital Electronics - Boolean Algebra and Logic Simplification - Discussion

Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 6)
6.
One of De Morgan's theorems states that . Simply stated, this means that logically there is no difference between:
a NOR and an AND gate with inverted inputs
a NAND and an OR gate with inverted inputs
an AND and a NOR gate with inverted inputs
a NOR and a NAND gate with inverted inputs
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.

Rbvsuresh said:   7 years ago
By using Demorgans theorem (x+y)'=x'.y' is AND GATE.
(x'.y')=(x+y)' is NOR GATE.

So, option C is correct.
(1)

Rohit said:   7 years ago
Please explain the answer.

Divya said:   10 years ago
OR gate have complement then produce the NOR gate and AND gate separated by dot (.).

Subhashis Maitra said:   1 decade ago
Since the LHS of the expression is the logical expression of two inputs NOR Gate and the RHS of the expression consists of two inverted inpuuts of A and B, that is two inverted input are ANDed to get the RHS of the expression and since according to Demorgan Laws, the complement of the sum of two or more variables are equivalent to the product of the complement of the individual variables, we can say that a NOR gate is equivalent to an AND gate with inverted inputs.

Anuroop said:   1 decade ago
Left side of the equation is the output of a two input nor gate (which simply inverts the output of an or gate) and right side of the equation is the output of an and gate with the inverted inputs (output of the and gate is the product of the given inputs).

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