Digital Electronics - Boolean Algebra and Logic Simplification - Discussion
Discussion Forum : Boolean Algebra and Logic Simplification - Filling the Blanks (Q.No. 4)
4.
The standard SOP form of the expression 
is ________.
is ________.
Discussion:
5 comments Page 1 of 1.
Sundar said:
1 decade ago
A'B + A'C
= A'B(C+C') + A'C(B+B')
= A'BC + A'BC' + A'CB + A'CB'
= A'BC + A'BC' + A'BC + A'B'C (After aligned in ABC sequence)
= (A'BC) + A'BC' + (A'BC) + A'B'C
= A'BC + A'BC' + A'B'C
= A'B'C + A'BC' + A'BC [Rewritten as per Option B]
Therefore, the correct answer is.
= A'B(C+C') + A'C(B+B')
= A'BC + A'BC' + A'CB + A'CB'
= A'BC + A'BC' + A'BC + A'B'C (After aligned in ABC sequence)
= (A'BC) + A'BC' + (A'BC) + A'B'C
= A'BC + A'BC' + A'B'C
= A'B'C + A'BC' + A'BC [Rewritten as per Option B]
Therefore, the correct answer is
.
(1)
Lakshan said:
1 decade ago
Can you please explain this to me ?
Reena said:
1 decade ago
In case of this equation A'B+A'C is not the std of the SOP we product the missing character such that (C+C') and(B+B')
which will result in
A'BC+A'BC'+A'BC+A'B'C = A'BC+A'BC'+A'B'C
Plz cross check.
which will result in
A'BC+A'BC'+A'BC+A'B'C = A'BC+A'BC'+A'B'C
Plz cross check.
Habibur said:
1 decade ago
Reena is right.
VARUN said:
1 decade ago
A'B(0+1)+A'(0+1)C {{C consist of C & C' then C = 1 & C' = 0}}.
= A'BC'+A'BC+A'B'C+A'BC.
= A'BC'+A'BC+A'B'C.
= A'BC'+A'BC+A'B'C+A'BC.
= A'BC'+A'BC+A'B'C.
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