Digital Electronics - Boolean Algebra and Logic Simplification - Discussion
Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 35)
35.
Mapping the standard SOP expression , we get
Discussion:
4 comments Page 1 of 1.
Sravan kumar said:
8 years ago
In k-map, we have to take
0 1 3 2
4 5 7 6
8 9 11 10
12 13 15 14
But in this case,
0 1 2 3
4 5 6 7
8 9 10 11
12 13 14 15
0 1 3 2
4 5 7 6
8 9 11 10
12 13 15 14
But in this case,
0 1 2 3
4 5 6 7
8 9 10 11
12 13 14 15
Bhagya h s said:
8 years ago
Is it need to simplify this equation else directly can we apply to KMAP?
Sunil N said:
5 years ago
It should be:
0 1 3 2
4 5 7 6
12 13 15 14
8 9 11 10
0 1 3 2
4 5 7 6
12 13 15 14
8 9 11 10
Saroha said:
8 years ago
Agree @Sravan Kumar.
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