Digital Electronics - Boolean Algebra and Logic Simplification - Discussion
Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 26)
26.
The truth table for the SOP expression 
has how many input combinations?
has how many input combinations?Discussion:
6 comments Page 1 of 1.
Veyant Singh said:
8 years ago
Here we simplify it multiply with ab(c+c')*ab+(a+a')*b'c.
Here we get,
Abc+abc'+ab'c+a'b'c.
Hence there is 3input a b c.
Thus total no of IP combination is 2pow 3 =.8.
Here we get,
Abc+abc'+ab'c+a'b'c.
Hence there is 3input a b c.
Thus total no of IP combination is 2pow 3 =.8.
Sridhar sharma said:
7 years ago
Since there are 3 inputs in the sum,
Number of combinations = 2^n,
whrer "n = no of inputs'.
So, 2^3 = 8.
Number of combinations = 2^n,
whrer "n = no of inputs'.
So, 2^3 = 8.
(1)
Gautami reddy said:
1 decade ago
Its has 3 inputs A, B, C so no. Of input combinations is 2^n here n=3 so 2^3=8 hence 8 input combinations.
Sunny said:
8 years ago
Can anyone tell me what will be its solution if its an equation?
Mohan said:
1 decade ago
2 to the power of 3 = 8.
Dheeraj said:
1 decade ago
Since it has 3 inputs.
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