Digital Electronics - Boolean Algebra and Logic Simplification - Discussion
Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 13)
13.
A truth table for the SOP expression 
has how many input combinations?
has how many input combinations?Discussion:
5 comments Page 1 of 1.
Abhiseksahoo said:
9 years ago
For n variables, the number of input combinations is 2^n. So here n = 3 so 2^3 = 8. There are 8 combinations.
(1)
Gautami reddy said:
1 decade ago
For n variables the no of input combinations are 2^n so here n=3 so 2^3=8 there are 8 combinations.
Manikandan said:
1 decade ago
n variables the no.of input combinations are 2^n so here n=3 so 2^3=8 there are 8 combinations.
DHUWARAKGA SHRI said:
1 decade ago
Number of input variables used is 3(A, B, C). So, number of input combinations are 8(0 to 7).
GOWRI DHANABAL said:
1 decade ago
If you the expression, it has three variables. so the number of input combination is 2^3=8
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