Digital Electronics - Boolean Algebra and Logic Simplification - Discussion
Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 43)
43.
Determine the binary values of the variables for which the following standard POS expression is equal to 0. 
Discussion:
19 comments Page 2 of 2.
Reddy said:
9 years ago
Both B and C are correct 1.0 = 0, 0.1 = 0.
Sam said:
8 years ago
The values of A, B, C are taken as inputs or outputs? Please explain.
Vaishali said:
8 years ago
Option A is correct. I agree.
Vaishu said:
8 years ago
Place given value into the expression and calculate the result.
Sita said:
7 years ago
B is the correct answer.
Jorriam Tsotetsi said:
7 years ago
Both A and C are correct.
(A + B' + C)(A' + B + C'),
C=(0 + 0 + 0)(1 + 0 + 1),
=(0 + 1 + 0)(0 + 0 + 0),
=(1)(0),
=(0).
For A.
(A + B' + C)(A' + B + C'),
C=(0 + 0 + 0)(1 + 0 + 1),
=(0 + 1 + 0)(0 + 0 + 0),
=(1)(0),
=(0).
For A.
Alexandar said:
6 years ago
I think A is Correct bcoz the given binary values represent the values for the inputs (A,B,C), then
(0+1+0)=> for (A+B'+C)=(0+0+0)=0&
(1+0+1)=>for (A'+B+C')=(0+0+0)=0 so;
(A+B'+C).(A'+B+C')= 0.0 = 0.
(0+1+0)=> for (A+B'+C)=(0+0+0)=0&
(1+0+1)=>for (A'+B+C')=(0+0+0)=0 so;
(A+B'+C).(A'+B+C')= 0.0 = 0.
VISCOS said:
6 years ago
NB:In POS form,"input with a bar " is assigned '1' and '0' if there is no bar unlike the SOP form.
(A+B'+C).(A'+B+C') = (0 + 1 + 0).(1 + 0 + 1),
So, A is correct.
(A+B'+C).(A'+B+C') = (0 + 1 + 0).(1 + 0 + 1),
So, A is correct.
Pavan Krishna said:
3 years ago
Correct answer: B.
A=1,B=0,C=1.
(A+B'+C)(A'+B+C'),
(1+1+1)(0+0+0),
(1)(0).
=0, ONLY B is correct.
A=1,B=0,C=1.
(A+B'+C)(A'+B+C'),
(1+1+1)(0+0+0),
(1)(0).
=0, ONLY B is correct.
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